Ice is put in a calorimeter. 1630 J raises it and its contents from 270 K to 272 K, and 52345 J raises it from 272 K to 274 K. c ice = 2100 , c water = 4200 J / ( kg K ) , L f = 3.36 × 1 0 5 J /

Question

Ice is put in a calorimeter. 1630 J raises it and its contents from 270 K to 272 K, and 52345 J raises it from 272 K to 274 K. c ice ​ = 2100 , c water ​ = 4200 J / ( kg K ) , L f ​ = 3.36 × 1 0 5 J / kg . Find the heat capacity of the calorimeter in J/K.

TestHub · Accepted Answer

Let X = C + 2100 m . First run: 2 X = 1630 , so X = 815 . Second run: X + 336000 m + ( C + 4200 m ) = 52345 . With C = 815 − 2100 m : 1630 + 338100 m = 52345 , so m = 0.15 kg and C = 815 − 315 = 500 J / K .

Physics - Heat & Thermo Question with Solution | TestHub

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