Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoKTGEasy2 minPYQ_2019

PhysicsEasysingle choice

For given gas at $1 a t m$ pressure, $r m s$ speed of the molecules is $200 m / s$ at $127 ° C .$ At $2 a t m$ pressure and at $227 ° C,$ the $r m s$ speed of the molecules will be:

Options:

Answer:

Solution:

$V_{r m s} = \sqrt{\frac{3 R T}{M}} \Rightarrow V_{r m s} \propto \sqrt{T}$
$\frac{V_{1}}{V_{2}} = \sqrt{\frac{T_{1}}{T_{2}}}$
$\frac{200}{V_{2}} = \sqrt{\frac{400}{500}}$
$V_{2} = 100 \sqrt{5} m / s$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:KTG

⏱ 2mℹ️ Source: PYQ_2019

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