Physics - Heat & Thermo Question with Solution | TestHub

Given, mass of copper block$m=5 \mathrm{kg}$

Change in temperature$\left(\Delta \text{t}\right)=500°\text{C}$

Specific heat$s=0.39 \mathrm{J} {(\mathrm{g}-°\mathrm{C})}^{-1}$

Latent heat of fusion of water$L=335 \mathrm{J} {\mathrm{g}}^{-1}$

Heat energy absorbed by copper block,${\mathit{\text{Q}}}_1=\mathit{\text{ms}}\Delta \mathit{\text{t}}$

Let$m\text{'}$$\mathrm{kg}$of ice be melted.

Heat energy required to melt ice,$Q_2=m\text{'}L$

But heat energy absorbed by copper block is heat energy utilised by ice in melting,$Q_1=Q_2$.
$\mathit{\text{ms}}\Delta \mathit{\text{t}}={\mathit{\text{m}}}^{\text{'}}\mathit{\text{L}}$
or${\mathit{\text{m}}}^{\text{'}}=\frac{\mathit{\text{ms}}\Delta \mathit{\text{t}}}{\mathit{\text{L}}}$$=\frac{5\times 0.39\times 500}{335}=2.9 \mathrm{kg}$