Physics - Heat & Thermo Question with Solution | TestHub

$V{T}^2=$ const: $V_0\to V_0/4\Rightarrow T_0\to 2T_0;P_f=\frac{2R{T}_0}{V_0/4}=8P_0$, so $\Delta P=7P_0$ (B true).

$$\Delta U=\frac{5R}{2}\left(T_0\right)=2.5P_0{V}_0\text{ (C true). }$$

$$\begin{array}{rlr}& P=RT/V=R{T}_0\sqrt{V_0}{V}^{-3/2}:W={\int }_{V_0}^{V_0/4}PdV=-2P_0{V}_0,\text{ not }-P_0{V}_0\text{ (D false). }& \Delta Q=\Delta U+W=2.5P_0{V}_0-2P_0{V}_0=\frac{P_0{V}_0}{2}\text{ (A true). }\end{array}$$