A conveyor belt is moving with a constant velocity 2 m/s. Block is projected with speed of 4 m/s in opposite direction of velocity of belt. if mass of block is '4 kg' and coefficient of fric

Question

A conveyor belt is moving with a constant velocity 2 m/s. Block is projected with speed of 4 m/s in opposite direction of velocity of belt. if mass of block is '4 kg' and coefficient of friction is 0.2. Find work done against friction on conveyor belt up to the instant when slipping between block and belt ceases :

TestHub · Accepted Answer

Time taken to slipping ceased 4 = − 2 + μg t ⇒ [ t = ( 2 ) 6 ​ = 3 sec ] Work done againt friction on conveyor belt ​ = μ ( mg ) × ( x ) ​ = 0.2 × 4 × 10 × ( 2 × 3 ) = 48 Joule ​

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JEE Main 2028 (Class 11)