A particle moves with a velocity of 4 i ^ − 2 j ^ + 2 k ^ m s - 1 under the influence of a constant force F → = 10 i ^ + 3 j ^ - 2 k ^ N . The instantaneous power applied to the particle is

P = F → ⋅ v → = 4 i ^ - 2 j ^ + 2 k ^ · 10 i ^ + 3 j ^ - 2 k ^ = 40 - 6 - 4 ∴ P = 30 W

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PhysicsW.E.P.PowerEasy2 minPYQ_2020

PhysicsEasynumerical

A particle moves with a velocity of $(4 \hat{i} - 2 \hat{j} + 2 \hat{k}) {m s}^{- 1}$ under the influence of a constant force $\vec{F} = (10 \hat{i} + 3 \hat{j} - 2 \hat{k}) N$ . The instantaneous power applied to the particle is

Answer:

30.00

Solution:

$P = \vec{F} \cdot \vec{v}$

$= (4 \hat{i} - 2 \hat{j} + 2 \hat{k}) \cdot (10 \hat{i} + 3 \hat{j} - 2 \hat{k})$ $= 40 - 6 - 4$

$∴ P = 30 W$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Power

⏱ 2mℹ️ Source: PYQ_2020

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