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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Work kinetic energy theoremHard2 minQB

PhysicsHardsingle choice

A block is placed on rough hill. Block is slowly moved over the surface. One of the force of magnitude 'F' is applied perpendicular to the surface and other is always parallel to surface. Select correct statement :

Options:

Answer:

Solution:

$N = mg cos (θ) + F$ for very small displacement $\int dw = \int - μ [mg cos (θ) + F] \cdot ds = - μ [mgx + Fs]$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Work kinetic energy theorem

⏱ 2mℹ️ Source: QB

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