Physics - W.E.P. Question with Solution | TestHub

$\begin{array}{rl}7.2\mathrm{km}/\mathrm{ram}& =\frac{7.2\times \frac{5}{18}\mathrm{m}/\mathrm{s}}{7/2^2}\\ & =\frac{72\times 5}{10\times 18}=2\mathrm{m}/\mathrm{s}\end{array}$ firt case EC $\frac{1}{2}k{x}^2=\frac{1}{2}m{v}^2$ $\Rightarrow \frac{1}{7}k{\left(30\times 10^{-2}\right)}^2=\frac{1}{2}\times 3.628\times (2{)}^2$ $k=\frac{4\times 3.628}{9\times 10^{-2}}$ $\begin{array}{rl}\text{ EC }& \frac{1}{2}k{x}^2=\frac{1}{2}m{v}^2\\ \Rightarrow & \frac{1}{2}k{\left(30\times 10^{-2}\right)}^2=\frac{1}{2}\times 3.628\times (2{)}^2\\ k& =\frac{4\times 3.628}{9\times 10^{-2}}\end{array}$ energy potential enrgy when conpressed at $15\mathrm{cm}$ $\begin{array}{rl}\Rightarrow & \frac{1}{2}k{\left(15\times 10^{-2}\right)}^2\\ =& \frac{1}{2}\times \frac{4\times 3.628}{9\times 10^{-2}}\times 225\times 10^{-4}\\ =& \frac{1639\times 10^{-2}}{9}\\ =& 182.206\times 10^{-2}\end{array}$ $\begin{array}{rl}& \Rightarrow \frac{1}{2}k(15\times 10^2\\ & =\frac{1}{2}\times \frac{\alpha \times 3.628}{9\times 10^{-2}}\times 225\times 10^{-4}\\ & =\frac{1639\times 10^{-2}}{9}\\ & =182.206\times 10^{-2}\end{array}$