Start Free Mock LoginAlready registered? Login here

Physics - Practical physics Question with Solution | TestHub

PhysicsPractical physicsMiscellaneousEasy2 minQB

PhysicsEasysingle choice

Smallest division on the main scale of given Vernier calipers is $0.5 m m$ . Vernier scale has $25$ divisions and these coincide with $24$ main scale divisions. The least count of Vernier callipers is

Options:

Answer:

Solution:

$25 V S D = 24 M S D$

$1 V S D = \frac{24}{25} M S D$ .......(i)

The least count of Vernier calipers is $L C = 1 M S D - 1 V S D$

$= 1 M S D - \frac{24}{25} M S D = \frac{1}{25} M S D$ (using (i))

As $1 M S D = 0.5 m m$ (given)

$∴ L C = \frac{1}{25} (0.5 m m) = 0.02 m m = 0.002 c m$

Stream:JEESubject:PhysicsTopic:Practical physicsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...