Physics - Practical physics Question with Solution | TestHub

PhysicsPractical physicsMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

Two full turns of the circular scale of a screw gauge cover a distance of $1 mm$ on its main scale. The total number of divisions on the circular scale is $50$ . Further, it is found that the screw gauge has a zero error of $- 0.03 mm$ . While measuring the diameter of a thin wire, a student notes the main scale reading of $3 mm$ and the number of circular scale divisions, in line with the main scale, as $35$ . The diameter of the wire is

Options:

Answer:

Solution:

Least count of the screw gauge,

$= \frac{0.5 mm}{50} = 0.01 mm$

Main scale reading $= 3 mm$

Vernier scale reading $= 35$

$∴$ Observed reading $= 3 + 0.35 = 3.35 mm$
Zero error $= -0.03 mm$

$∴$ Actual diameter of the wire $= 3.35 - (- 0.03) = 3.38 mm$

Stream:NTA_ABHYASSubject:PhysicsTopic:Practical physicsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...