Physics - Practical physics Question with Solution | TestHub
The circular scale of a screw gauge consists of 50 divisions and the linear distance travelled by screw in one complete rotation is equal to 0.5 mm and it is equal to the value of one pitch scale division. When nothing is placed between the studs, division of circular scale coincides with the index line of pitch scale and zero of the pitch scale is just inside the circular scale. Now a thin plate of thickness 4.68 mm is inserted between the studs by unscrewing the circular scale and fit it just tight to measure its thickness.The minimum number of rotations to be done by the ratchet in order to insert the plate during unscrewing is , ( n is an integer then )
Answer:
Solution:
From the given inform after, the screw gauge has negative zero error of 4 circular scale divisions. To allow 4.68 mm thick plate, the screw gauge to be conscred by 9.5 rotation
i.e. thickness of plate nearly