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Physics - Practical physics Question with Solution | TestHub

PhysicsPractical physicsMiscellaneousMedium2 minPYQ_2012

PhysicsMediumsingle choice

In a slide caliper, $(m + 1)$ number of vernier divisions is equal to $m$ number of smallest main scale divisions. If $d$ unit is the magnitude of the smallest main scale division, then the magnitude of the vernicr constant is

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Solution:

$(m + 1)$ vernier division $= m$ main scale division One division on vernier scale $= (\frac{m}{m + 1})$ division on main scale Vernier constant $= (1 - \frac{m}{m + 1}) d = \frac{d}{m + 1}$

Stream:WBJEESubject:PhysicsTopic:Practical physicsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2012

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