A ladder PQ of length 5 m inclined to a vertical wall is slipping over a horizontal surface with a velocity of $2 m s^{- 1}$ , When Q is at a distance 3 m from the ground. Calculate the velocity of centre of mass the rod at this moment in nearest integers?

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y d t d y ​ V y ​ ( V co m ​ ) x ​ ( V co m ​ ) y ​ V co m ​ ​ = V 2 − x 2 ​ = V 2 − x 2 ​ − x ​ ⋅ d t d x ​ = − 2 3 ​ m / s = d t d ​ ( 2 x ​ ) = 1 = d t d ​ ( 2 y ​ ) = 4 3 ​ = 1 2 + ( 4 3 ​ ) 2 ​ = 4 5 ​ ​

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