Chemistry - Solid State Question with Solution | TestHub

Given that$\text{ρ}=2.75\text{g}\text{c}{\text{m}}^{-3}$

we need to find type of unit cell
$\begin{array}{l}\end{array}$
$\begin{array}{l}\therefore \text{ρ}=\frac{\text{Z}\times \text{M}}{{\text{N}}_{\text{A}}{\text{a}}^3}\\ \\ \because \text{Z}=\frac{\text{ρ}\times {\text{N}}_{\text{A}}\times {\text{a}}^3}{\text{M}}\\ \\ =\frac{2.75\times 6.023\times {10}^{23}\times {\left(654\times {10}^{-10}\right)}^3}{119}\end{array}$

$\therefore \text{Z}\simeq 4\text{S}\text{o}\text{f}\text{c}\text{c}\text{u}\text{n}\text{i}\text{t}\text{c}\text{e}\text{l}\text{l}$

In FCC 1 atm surrounded by 6 atoms so coordination number is 6.