A non-stoichiometric compound Cu 1.8 S is formed due to the incorporation of Cu 2+ ions in the lattice. What is the mole percentage of Cu 2+ present in the compound?

In one mole, Let there be Cu +2 =x moles ∴ Cu + = 1.8 − x moles ∵ 2 x + 1.8 − x 1 = + 2 x = 0.2 % Cu + 2 = 0.2 1.8 × 100 = 11.11 %

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Chemistry - Solid State Question with Solution | TestHub

ChemistrySolid StateMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

A non-stoichiometric compound Cu_1.8S is formed due to the incorporation of Cu²⁺ions in the lattice. What is the mole percentage of Cu²⁺present in the compound?

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Answer:

Solution:

In one mole, Let there be Cu⁺²=x moles

$∴ {Cu}^{+} = 1.8 - x$ moles

$∵ 2 x + (1.8 - x) 1 = + 2$

$x = 0.2$

$% {Cu}^{+ 2} = \frac{0.2}{1.8} \times 100 = 11.11 %$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Solid StateSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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