In a solid AB having N a C l structure, ‘A’ atoms occupy the corners & face centre of the cubic unit cell. If all the face centered atoms along one of the axes are removed, then the resultant stoichio

Question

In a solid AB having N a C l structure, ‘A’ atoms occupy the corners & face centre of the cubic unit cell. If all the face centered atoms along one of the axes are removed, then the resultant stoichiometry of the solid is

TestHub · Accepted Answer

Atom A occupies all corner and face center of unit cell and atom B in all octahedral void. As all atoms from face center from one axis is removed, hence number of atom A in unit cell remains 3 and B as 4.
$A = 8 \times \frac{1}{8} + 6 \times \frac{1}{2} = 4$
$A = 4 - 2 \times \frac{1}{2} = 3$ after removing atoms
$B = 12 \times \frac{1}{4} + 1 \times 1 = 4$
Formula of compound is $A_{3} B_{4}$

Chemistry - Solid State Question with Solution | TestHub

Options:

Doubts & Discussion