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Chemistry - Solid State Question with Solution | TestHub

ChemistrySolid StateCubic CrystalsMedium2 minPYQ_2010

ChemistryMediumsingle choice

The radius of $Na^{+}$ is $95 pm$ and that of $Cl$ - ion is $181 pm$ . Hence, the coordination number of $Na^{+}$ will be

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Answer:

Solution:

$\frac{Radius of cation, r ^{+}}{Radius of anion, r ^{-}} = \frac{95}{181} = 0.525$ As this value lies in between $0.414 - 0.732$ , thus, the coordination number of $Na^{+}$ ion will be $6.$

Stream:VITEEESubject:ChemistryTopic:Solid StateSubtopic:Cubic Crystals

⏱ 2mℹ️ Source: PYQ_2010

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