Chemistry - Solid State Question with Solution | TestHub

Volume of atom in a cell$\text{=}\frac{\text{4}}{\text{3}}{\text{πr}}^{\text{3}}\text{×}\text{N}\left(\text{N}\text{=}\text{4}\text{for}\text{fcc}\right)$
$=\frac{4}{3}\times \mathrm{\pi }{\mathrm{r}}^3\times 4=\frac{16}{3}\mathrm{\pi }{\mathrm{r}}^3$