One atom of an element ' X ' weighs 6.6667 × 1 0 − 23 g . The number of gram-atoms in 40 kg of it is ( N A = 6 × 1 0 23 )

Mass of one atom is 6.6667 × 1 0 − 23 . S o , in 40 k g , n u mb ero f a t o m s = 6.6667 × 1 0 − 23 1 × 40000 = 6 × 1 0 26 ∴ N u mb ero f g r am − a t o m s = 6 × 1 0 23 6 × 1 0 26 = 1000

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One atom of an element ' X ' weighs $6.6667 \times 1 0^{- 23} g$ . The number of gram-atoms in 40 kg of it is ( $N_{A} = 6 \times 1 0^{23}$ )

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Answer:

Solution:

Mass of one atom is $6.6667 \times 1 0^{- 23}$ .

$S o, in 40 k g, n u mb ero f a t o m s = \frac{1}{6.6667 \times 1 0 ^{- 23}} \times 40000 = 6 \times 1 0^{26}$

$∴ N u mb ero f g r am - a t o m s = \frac{6 \times 1 0 ^{26}}{6 \times 1 0 ^{23}} = 1000$

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Calculation of mole

⏱ 2mℹ️ Source: QB

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