Chemistry - Mole Concept Question with Solution | TestHub

⇒ equivalents at anode = equivalents at cathode
⇒ equivalents of oxygen = equivalents of aluminium
Number of equivalents of oxygen$=\frac{201.6}{5.6}=36$
(Equivalent volume of oxygen = 5.6 litre at NTP)
So number of equivalents of Al = 36
Mass of aluminium$=36\times 9$g
Number of moles of aluminium$=\frac{\mathrm{w}\mathrm{e}\mathrm{i}\mathrm{g}\mathrm{h}\mathrm{t }}{\mathrm{a}\mathrm{t}\mathrm{o}\mathrm{m}\mathrm{i}\mathrm{c }\mathrm{w}\mathrm{e}\mathrm{i}\mathrm{g}\mathrm{h}\mathrm{t}}=\frac{36\times 9}{27}=12$.