Chemistry - Mole Concept Question with Solution | TestHub

Moles of ' C ' $={\mathrm{n}}_{{\mathrm{CO}}_2}=\frac{1.46}{44}=0.033$
Moles of ' C ' $={\mathrm{W}}_{\mathrm{C}}=0.033\times 12$
Moles of 'H' $=2\times {\mathrm{n}}_{{\mathrm{H}}_2\mathrm{O}}=2\times \frac{0.567}{18}=0.063$
Mass of ' H ' $=0.0063$
Mass of Oxygen $(\mathrm{O})=1-\left({\mathrm{W}}_{\mathrm{c}}+{\mathrm{W}}_{\mathrm{H}}\right)$ $=1-(0.033\times 12+0.063\times 1)=0.541\mathrm{gm}$
Moles of ' O ' $=\frac{0.541}{16}=0.033$
Empirical formula $={\mathrm{CH}}_2\mathrm{O}$
Empirical formula mass $=30$.