Chemistry - Electrochemistry Question with Solution | TestHub

${\mathrm{Al}}^{3\ast }+3{\mathrm{e}}^{-}⟶\mathrm{Al}$ 1 mole of electron $=1\mathrm{F}=96500$ coulombs $\therefore 3{\mathrm{e}}^{-}=3\mathrm{F}=3\times 96500=2,89,500=2.895\times 10^5$ coulombs