Chemistry - Electrochemistry Question with Solution | TestHub

ChemistryElectrochemistryGalvanic cells/Nernst Equation/Concentration CellsMedium2 minPYQ_2002

ChemistryMediumstatement

EMF of a cell in terms of reduction potential of its left and right electrodes is

Answer:

Solution:

$E_{cell} = Reduction potential of cathode (right) - reduction potential of anode (left) = E_{right} - E_{left}$

Stream:JEESubject:ChemistryTopic:ElectrochemistrySubtopic:Galvanic cells/Nernst Equation/Concentration Cells

⏱ 2mℹ️ Source: PYQ_2002

Loading discussions...