What is the molar conductivity of 0 ⋅ 1 M NaCl if it's conductivity is 1 ⋅ 06 × 1 0 − 2 Ω − 1 cm − 1 ?

k = 1.06 × 1 0 − 2 Ω − 1 cm − 1 , C = 0.1 M Molar conductivity, Λ m = C k × 1000 Λ m = 0.1 1.06 × 1 0 − 2 × 1000 = 1.06 × 1 0 2 Ω − 1 cm 2 mol − 1

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ChemistryElectrochemistryConductance/conductivity/^mEasy2 minPYQ_2020

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What is the molar conductivity of $0 \cdot 1$ M NaCl if it's conductivity is $1 \cdot 06 \times 1 0^{- 2} Ω^{- 1} cm^{- 1}$ ?

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Solution:

$k = 1.06 \times 1 0^{- 2} Ω^{- 1} cm^{- 1}, C = 0.1 M$ Molar conductivity, $Λ_{m} = \frac{k \times 1000}{C}$ $Λ_{m} = \frac{1.06 \times 1 0 ^{- 2} \times 1000}{0.1} = 1.06 \times 1 0^{2} Ω^{- 1} cm^{2} mol^{- 1}$

Stream:MHT_CETSubject:ChemistryTopic:ElectrochemistrySubtopic:Conductance/conductivity/^m

⏱ 2mℹ️ Source: PYQ_2020

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