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Chemistry - Electrochemistry Question with Solution | TestHub

ChemistryElectrochemistryFaraday's Law of Electrolysis/Electrolytic CellsMedium2 minQB

ChemistryMediumsingle choice

Passage / Comprehension

The cell potential for the chemical reaction : $Hg_{2}^{^{2 +}} (a q) + N O_{3}^{-} (a q) + 3 H_{3} O^{+} (a q) ⟶ 2 H g^{2 +} (a q) + H N O_{2} (a q) + 4 H_{2} O (l)$

is measured under standard conditions in the electrochemical cell shown in the accompanying diagram.

How many moles of electrons pass through the circuit when 0.60 mole of $Hg^{2 +}$ and 0.30 mole of $HNO_{2}$ are produced in the cell that contain 0.50 mole of $Hg_{2}^{2 +}$ and 0.40 mole of $NO_{3}^{-}$ at the beginning of the reaction?

Options:

Answer:

Solution:

Moles of electron needed $= 2 \times$ moles of $HNO_{2}$ formed.

Stream:JEESubject:ChemistryTopic:ElectrochemistrySubtopic:Faraday's Law of Electrolysis/Electrolytic Cells

⏱ 2mℹ️ Source: QB

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