Chemistry - Electrochemistry Question with Solution | TestHub

$$\mathrm{Q}=\mathrm{I}\times \mathrm{t}=5\times 200=1000\mathrm{C}$$ The charge of one electron is $1.602\times 10^{-19}\mathrm{C}$ No. of electrons passed $=\frac{1000\mathrm{C}}{1.602\times 10^{-19}\mathrm{C}}=6.24\times 10^{21}$