Match the following.
(1) Energy of ground state of $H e^{+}$ (p) 6.04 eV
(2) Potential energy of 1 orbit of H atom (q) -27.2 eV
(3) Kinetic energy of II excited state of $H e^{+}$ (r) 54.4 eV
(4) Ionisation potential of $H e^{+}$ (s) -54.4 eV

Question

Match the following.

(1)	Energy of ground state of $H e^{+}$	(p)	6.04 eV
(2)	Potential energy of 1 orbit of H atom	(q)	-27.2 eV
(3)	Kinetic energy of II excited state of $H e^{+}$	(r)	54.4 eV
(4)	Ionisation potential of $H e^{+}$	(s)	-54.4 eV

TestHub · Accepted Answer

Energy of G.S. of H e + = E H × Z 2 = − 13.6 × 4 = − 54.4 eV Ionisation potential of H e + = E ∞ - E 1 = − − 54.4 = 54.4 eV T.E. of H of 1 orbit = − 13.6 eV 2 T.E. = P.E. and K .E = − T . E P .E . = − 2 × 13.6 = − 27.2 eV T.E. of H of II excited state = - 13.6 9 × 4 of He = − 6.04 eV K .E . = − (T .E .) = − − 6.04 eV = + 6.04 eV

Chemistry - Atomic Structure Question with Solution | TestHub

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