Chemistry - Atomic Structure Question with Solution | TestHub

ChemistryAtomic StructureBohr's Atomic ModelMedium2 minQB

ChemistryMediumsingle choice

If the binding energy of the electron in a hydrogen atom is 13.6 eV , the energy required to remove the electron from the first excited state of $Li^{2 +}$ is :

Options:

Answer:

Solution:

Li²⁺ is a hydrogen-like ion with $Z = 3$ .

First excited state corresponds to $n = 2$ .

Energy of nᵗʰ orbit: $E_{n} = - 13.6 \frac{Z ^{2}}{n ^{2}} e V$ .

$E_{2} = - 13.6 \frac{3 ^{2}}{2 ^{2}} = - 30.6 e V$

Ionization energy from this state equals the magnitude of $E_{2}$ .

Therefore, required energy = 30.6 eV.

Answer: (B) 30.6 eV

Stream:JEESubject:ChemistryTopic:Atomic StructureSubtopic:Bohr's Atomic Model

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...