Match each quantity of L i 2 + in Column I with the statements in Column II that are true for it ( E 1 = − 13.6 eV for H; 1 eV = 1.6 × 1 0 − 19 J ) ( a Column I entry may match more than one Column

Question

Match each quantity of L i 2 + in Column I with the statements in Column II that are true for it ( E 1 ​ = − 13.6 eV for H; 1 eV = 1.6 × 1 0 − 19 J ) ( a Column I entry may match more than one Column II entry): Column I (Quantity of L i 2 + ) Column II (Statement) (P) Energy of the ground state (1) +30.6 eV (Q) Kinetic energy in the first excited state (2) -122.4 eV (R) Potential energy in the third orbit (3) +122.4 eV (S) Ionisation energy (4) -27.2 eV ( 5 ) 1.96 × 1 0 − 17 J (6) a negative quantity Choose the option with the correct matching:

TestHub · Accepted Answer

(P) E 1 ​ = − 13.6 × 9 = − 122.4 eV (2), negative (6). (Q) n = 2 : KE = 122.4/4 = +30.6 eV (1). (R) n = 3 : PE = 2 E = 2 × ( − 13.6 × 9/9 ) = − 27.2 eV (4), negative (6). (S) IE = +122.4 eV (3) = 122.4 × 1.6 × 1 0 − 19 = 1.96 × 1 0 − 17 J (5). Correct matching: P to 2,6; Q to 1; R to 4,6; S to 3,5. Answer: (C).

Chemistry - Atomic Structure Question with Solution | TestHub

Options:

Doubts & Discussion

Column I (Quantity of $L i^{2 +})$	Column II (Statement)
(P) Energy of the ground state	(1) +30.6 eV
(Q) Kinetic energy in the first excited state	(2) -122.4 eV
(R) Potential energy in the third orbit	(3) +122.4 eV
(S) Ionisation energy	(4) -27.2 eV
	$(5) 1.96 \times 1 0^{- 17} J$
	(6) a negative quantity