Chemistry - Atomic Structure Question with Solution | TestHub

ChemistryAtomic Structurede-Broglie's Wave EquationEasy2 minPYQ_2024

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The de-Broglie's wavelength of an electron in the $4^{th}$ orbit is__________ $π a_{0} \cdot (a_{0} =$ Bohr's radius $)$

Answer:

Solution:

$2 π r_{n} = n λ_{d} 2 π a_{0} \frac{n ^{2}}{Z} = n λ_{d} 2 π a_{0} \frac{4 ^{2}}{1} = 4 λ_{d} λ_{d} = 8 π a_{0}$

Stream:JEESubject:ChemistryTopic:Atomic StructureSubtopic:de-Broglie's Wave Equation

⏱ 2mℹ️ Source: PYQ_2024

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