Chemistry - Atomic Structure Question with Solution | TestHub

One photon ionises one$\mathrm{Na}-$atom by elastic collision.

$\mathrm{NA} {\mathrm{hv}}_{\mathrm{photon}}\times {10}^{–3} (\mathrm{KJ} {\mathrm{mole}}^{–1})$

$6·022\times {10}^{23}\times 6·626\times {10}^{-34}\times {\mathrm{\upsilon }}_{\text{photon}}\times {10}^{-3}=495·5$

${\mathrm{\upsilon }}_{\text{photon}}=\frac{495·5}{6·022\times 6·626\times {10}^{-14}}$

$=12.41\times {10}^{14}$

$=1·241\times 10^{15} {\text{sec}}^{-1}$