Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Work kinetic energy theoremMedium2 minQB
PhysicsMediumsingle choice

A ring of mass m slides from rest on the smooth rod as shown in the figure, due to the block of mass m. Pulley and string are massless. Then find the speed of ring when the string becomes straight.

Options:

Answer:
B
Solution:

The block descends as the string shortens. Initially the string from ring to pulley has length h/cos60 = 2h; when the string becomes vertical its length is h, so the block falls by h. The block's speed equals the rate of shortening of the string, v_block = v_ring sin(theta); as the string becomes vertical theta -> 0, so the block's speed tends to zero at that instant. Energy conservation: mgh = (1/2) m v^2, giving v = sqrt(2gh). Answer: (B).

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Work kinetic energy theorem
2mℹ️ Source: QB

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