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PhysicsW.E.P.Work kinetic energy theoremEasy2 minPYQ_2020
PhysicsEasysingle choice

The velocity-time graph of a particle of mass10 kgis shown in the figure. The net work done on the particle in the first two seconds of the motion is

Options:

Answer:
C
Solution:

v=-5t+50

vat t=2=40

 K.E.=W.D. =12402-502×10

=-4500J

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Work kinetic energy theorem
2mℹ️ Source: PYQ_2020

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