Physics - W.E.P. Question with Solution | TestHub

Normal on the block: $N=mg\cos 37^{\circ }=100\times 0.8=80\mathrm{N}$

In the ground frame the block's velocity is the cart velocity plus the slide along the incline; the normal is perpendicular to the slide, so only the cart's 10 m/s contributes.

Forward component of the normal: $N\sin 37^{\circ }=80\times 0.6=48\mathrm{N}$, so power $P=48\times 10=480\mathrm{W}$ (constant).

$$W=Pt=480\times 2=960\mathrm{J}$$

Ans. (B)