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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Work kinetic energy theoremMedium2 minPYQ_2024

PhysicsMediumsingle choice

When kinetic energy of a body becomes 36 times of its original value, the percentage increase in the momentum of the body will be:

Options:

Answer:

Solution:

Kinetic energy $(K) = \frac{P ^{2}}{2 m}$ $\Rightarrow P = 2 mK$
If $K_{f} = 36 K_{i}$ So, $P_{f} = 6 P_{i}$ $% increase in momentum = \frac{P _{f} - P _{i}}{P _{i}} \times 100% = \frac{6 P _{i} - P _{i}}{P _{i}} \times 100% = 500%$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Work kinetic energy theorem

⏱ 2mℹ️ Source: PYQ_2024

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