A uniform solid hemisphere of mass m and radius R is attached to the roof with a chord of torsional constant C and performing torsional SHM. Then the time period (in seconds) of SHM is

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TestHub · Accepted Answer

Moment of inertia of a solid hemisphere about the vertical diameter: $I = \frac{2}{5} m R^{2}$ .

Torsional SHM: $T = 2 π I / C = 2 π \frac{2 m R ^{2}}{5 C}$ .

Substituting the given values (figure) gives $T = 4 s$ .

Answer: 4

Physics - SHM Question with Solution | TestHub

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