An object moves vertically with SHM just behind a wall. From the other side of the wall it is visible in each cycle for 2.0 s and hidden for 6.0 s. The maximum height reached by the object relative to

Question

An object moves vertically with SHM just behind a wall. From the other side of the wall it is visible in each cycle for 2.0 s and hidden for 6.0 s. The maximum height reached by the object relative to the top of the wall is 0.3 m. The amplitude of the motion is:

TestHub · Accepted Answer

T = 8 s. Visible when x > h , for T /4 , so cos ω t > cos ( π /4 ) : h = A / 2 ​ . Then A − A / 2 ​ = 0.3 , so A = 0.3/0.2929 = 1.02 ≈ 1.0 m.

Physics - SHM Question with Solution | TestHub

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