A mass M is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes SHM of time period T. If the mass is increased by m , the time period

Question

A mass M is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes SHM of time period T. If the mass is increased by m , the time period becomes 3 5 T ​ . Then the ratio of M m ​ is

TestHub · Accepted Answer

T = 2 π K M ​ ​ 3 5 T ​ = 2 π K M + m ​ ​ Dividing equation (ii) by equation (i), 3 5 ​ = M M + m ​ ​ . Squaring both the sides 9 25 ​ = M M + m ​ = 1 + M m ​ ⇒ M m ​ = 9 25 ​ − 1 = 9 16 ​

Physics - SHM Question with Solution | TestHub

Options:

Doubts & Discussion