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PhysicsW.E.P.Vertical circular motionEasy2 minQB
PhysicsEasynumerical

A particle is suspended by a light vertical inelastic string of lengthlfrom a fixed support. At its equilibrium position, it is projected horizontally with a speed6gl. What is the ratio of the tension in the string in its horizontal position to when the particle is vertically above the point of support?

Answer:
4.00
Solution:

For a givenu=6gl


At the horizontal position,

T1=mv12l=4 mg.......... (i)

At the highest point

T2+mg=mv22l=2 mgT2=mg......... (ii)

From the above equations, we get

T1T2=4

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Vertical circular motion
⏱ 2mℹ️ Source: QB

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