Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Calculation of workEasy2 minQB

PhysicsEasynumerical

A force $(3 x^{2} + 2 x - 5) N$ displaces a body from $x = 2 m$ to $x = 4 m$ . Work done by this force is ________ $J$ .

Answer:

58.00

Solution:

$W = \int_{x_{1}}^{x_{2}} F d x W = \int_{2}^{4} (3 x^{2} + 2 x - 5) d x W = [x^{3} + x^{2} - 5 x]_{2}^{4} W = [60 - 2] J = 58 J$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Calculation of work

⏱ 2mℹ️ Source: QB

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