Physics - W.E.P. Question with Solution | TestHub

$\because$ Net force required to lift a hook and load, ${\mathrm{F}}_{\text{net }}=1000+10000=11000\mathrm{N}$ $\because$ Power required to lift hook, $\mathrm{P}=\frac{\mathrm{W}}{\mathrm{t}}$ $\begin{array}{rl}\because \mathrm{W}& ={\mathrm{F}}_{\text{net }}\mathrm{d}\\ \mathrm{P}\times \mathrm{t}& ={\mathrm{F}}_{\text{net }}\mathrm{d}\\ \mathrm{P}& =\frac{{\mathrm{F}}_{\text{net }}\mathrm{d}}{\mathrm{t}}={\mathrm{F}}_{\text{net }}\left(\frac{\mathrm{d}}{\mathrm{t}}\right)={\mathrm{F}}_{\text{net }}\mathrm{V}\left[\text{ Here, }\mathrm{v}=\frac{\mathrm{d}}{\mathrm{t}}\right]\end{array}$ or $\mathrm{P}=11000\times 0.5=5500\mathrm{W}=5.5\mathrm{kW}$