A particle is displaced from (2, 0, 2) to (5, 4, 2) under influence of force F = 6 i ^ + 8 j ^ . If W is work done (in joule) then what is value of 20 W ?

d = ( 5 − 2 ) i ^ + ( 4 − 0 ) j ^ + ( 2 − 2 ) k ^ = 3 i ^ + 4 j ^ F = 6 i ^ + 8 j ^ ⇒ W = 18 + 32 = 50 J 20 W = 2.5

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PhysicsW.E.P.Calculation of workEasy2 minQB

PhysicsEasynumerical

A particle is displaced from (2, 0, 2) to (5, 4, 2) under influence of force $F = 6 \hat{i} + 8 \hat{j}$ . If W is work done (in joule) then what is value of $\frac{W}{20}$ ?

Answer:

2.50

Solution:

$d = (5 - 2) \hat{i} + (4 - 0) \hat{j} + (2 - 2) \hat{k} = 3 \hat{i} + 4 \hat{j}$

$F = 6 \hat{i} + 8 \hat{j} \Rightarrow W = 18 + 32 = 50 J$

$\frac{W}{20} = 2.5$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Calculation of work

⏱ 2mℹ️ Source: QB

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