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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Work kinetic energy theoremMedium2 minQB

PhysicsMediuminteger

A particle moves according to equation $x = 10 sin 2 π t$ , $y = 10 cos 2 π t$ . Find the work (in J) performed by the net force from $t = 0$ to $t = 5$ seconds.

Answer:

Solution:

$x = 10 sin 2 π t, y = 10 cos 2 π t \Rightarrow x^{2} + y^{2} = 100$ : uniform circular motion.

Speed is constant, so $Δ K E = 0$ from t = 0 to 5 s.

Work done by the net force = $Δ K E = 0 J$ .

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Work kinetic energy theorem

⏱ 2mℹ️ Source: QB

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