Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Conservative force & potential energyMedium2 minQB

PhysicsMediuminteger

For the Force $\overline{F} = Axy \hat{i} + Bx^{2} \hat{j}$ to be conservative where $A, B$ are positive integers, what is the minimum value of $A + B$ ?

Answer:

Solution:

For conservative force $\frac{\partial F _{y}}{\partial x} = \frac{\partial F _{x}}{\partial y}$ or $\nabla \times F = 0$ .

$\hat{i} \frac{\partial}{\partial x} F_{x} \hat{j} \frac{\partial}{\partial y} F_{y} \hat{k} \frac{\partial}{\partial z} F_{z} = 0$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Conservative force & potential energy

⏱ 2mℹ️ Source: QB

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Physics - W.E.P. Question with Solution | TestHub

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JEE Main 2027 (Class 12+)

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