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PhysicsW.E.P.Work kinetic energy theoremEasy2 minQB

PhysicsEasysingle choice

Figure shows the vertical section of a frictionless surface. A block of mass 2 kg is released from rest from position A ; its KE as it reaches position C is $(g = 10 ms^{- 2})$

Options:

Answer:

Solution:

Applying WET

$m g (7) = K E$

$K E = 140$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Work kinetic energy theorem

⏱ 2mℹ️ Source: QB

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