A body of mass 3 kg is moving under the action of a force such that its displacement is given by the relation s = 1 3 t 2 , where t is time in second. The work done by the force in 2 s is

s = 1 3 t 2 v = d s d t = 2 3 t , a = d 2 s d t 2 = 2 3 F = m a = 3 × 2 3 = 2 N W = 2 × 1 3 t 2 At t = 2 s , W = 2 × 1 3 × 2 × 2 = 8 3 J

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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.MiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A body of mass $3 kg$ is moving under the action of a force such that its displacement is given by the relation $s = \frac{1}{3} t^{2}$ , where $t$ is time in second. The work done by the force in $2 s$ is

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Answer:

Solution:

$s = \frac{1}{3} t^{2}$

$v = \frac{d s}{d t} = \frac{2}{3} t, a = \frac{d^{2} s}{d t^{2}} = \frac{2}{3}$

$F = m a = 3 \times \frac{2}{3} = 2 N$

$W = 2 \times \frac{1}{3} t^{2}$

At $t = 2 s$ ,

$W = 2 \times \frac{1}{3} \times 2 \times 2 = \frac{8}{3} J$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:W.E.P.Subtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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