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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Vertical circular motionEasy2 minQB

PhysicsEasysingle choice

For a particle in uniform circular motion, the acceleration $\vec{a}$ at any point $P (R, θ)$ on the circular path of radius $R$ is (when $θ$ is measured from the positive $x$ -axis and $v$ is uniform speed):

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Solution:

Acceleration of a particle in uniform circular motion is directed towards the centre of the circle and its magnitude is $\frac{v^{2}}{R}$ . The radius vector is $\vec{r} = R \cos θ \hat{i} + R \sin θ \hat{j}$

Therefore, $\vec{a} = - \frac{v^{2}}{R} \hat{r} = \frac{v^{2}}{R} (- \cos θ \hat{i} - \sin θ \hat{j})$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Vertical circular motion

⏱ 2mℹ️ Source: QB

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