As shown in the figure, a particle of mass $10 kg$ is placed at a point $A .$ When the particle is slightly displaced to its right, it starts moving and reaches the point $B .$ The speed of the particle at $B$ is $x m s^{- 1}$ . (Take $g = 10 m s^{- 2})$ The value of $x$ to the nearest integer is

Question

Answer:

10.00

Solution:

Using work-energy theorem, $W_{g} = Δ K . E .$
$(10) (g) (5) = \frac{1}{2} (10) v^{2} - 0$
$v = 10 m s^{- 1}$ .

TestHub · Accepted Answer

Using work-energy theorem, W g = Δ K . E . ( 10 ) ( g ) ( 5 ) = 1 2 ( 10 ) v 2 - 0 v = 10 m s - 1 .

Physics - W.E.P. Question with Solution | TestHub

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