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Physics - W.E.P. Question with Solution | TestHub

PhysicsW.E.P.Calculation of workMedium2 minQB

PhysicsMediumsingle choice

A conveyor belt is moving with a constant velocity 2 m/s. Block is projected with speed of 4 m/s in opposite direction of velocity of belt. if mass of block is ' $4 kg^{'}$ and coefficient of friction is 0.2 . Find work done against friction on conveyor belt up to the instant when slipping between block and belt ceases :

Options:

Answer:

Solution:

Time taken to slipping ceased

$4 = - 2 + μ gt \Rightarrow [t = \frac{6}{( 2 )} = 3 sec]$

Work done againt friction on conveyor belt

$= μ (mg) \times (x) = 0.2 \times 4 \times 10 \times (2 \times 3) = 48 Joule$

Stream:JEESubject:PhysicsTopic:W.E.P.Subtopic:Calculation of work

⏱ 2mℹ️ Source: QB

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