Physics - W.E.P. Question with Solution | TestHub

Work done by the gun

=Total kinetic energy of the bullets

$=n=\frac{1}{2}m{v}^2$

$=240\times \frac{1}{2}\times 10\times {10}^{-3}{\left(600\right)}^2$

$=120\times \frac{1}{2}\times 10\times {10}^{-3}\times 600\times 600$

$\therefore Power of gun=\frac{work done}{time taken}$

$=\frac{120\times 10\times {10}^{-3}\times 600\times 600}{1min}$

$=\frac{120\times 10\times 360}{60}=120\times 10\times 6 \mathrm{W}$

$\frac{120\times 10\times 6}{1000} \mathrm{kW}=7.2 \mathrm{kW}$